Specialty faces the decision of how many Weather Teddy units to order for coming
ID: 448668 • Letter: S
Question
Specialty faces the decision of how many Weather Teddy units to order for coming holiday season. Members of the management team suggested order quantities of 15,000, 18,000, 24,000, 28,000 units. The wide range of order quantities suggested indicates considerable disagreement concerning the market potential. The product management team ask you for analysis of the stock-out probabilities for various order quantities, an estimate of the product potential, and to help make an order quantity recommendation. Specialty expects to sell Weather Teddy for $24 based on cost of $16 per unit. If inventory remains after the holiday season, Specialty will sell all surplus inventory for $5 per unit. After reviewing the sales history of similar products, Specialtys sales forecaster predicted and expected demand of 20,000 units with a .95 probability that demand would be between 10,000 units and 30,000 units. Prepare a managerial Report that addresses the following issues and recommends an order quantity for the Weather Teddy product.
Explanation / Answer
Let X be the demand for the toy. Then X follows normal distribution with mean = 20000 and standard deviation . Then
P(10000 < X < 30000) = 0.95
P((10000-20000)/ < (X-20000)/ < (30000-20000)/) = 0.95
From tables of areas under the standard normal curve (30000-20000)/ = 1.96
= (30000-20000)/1.96 =10000/1.96 = 5102
The demand distribution can be approximated by a normal distribution with mean µ = 20000 and standard deviation = 5102.
Probability of stock out with an order of K units is P(X > K) = P(Z > (K-20000)/5102), where Z is distributed as standard normal
Order (K)
(K-20000)/5102
P(X > K)
15000
-0.98001
0.836458876
18000
-0.392
0.652472052
24000
0.784006
0.216518215
28000
1.568013
0.058439102
3. The projected profit for the different order quantities and scenarios are given in the following table.
Order
Scenario 10000
Scenario 20000
Scenario 30000
15000
8*10000-11*5000 =25000
8*15000=120000
8*15000 = 120000
18000
8*10000-11*8000
= -8000
8*18000 = 144000
8*18000 = 144000
24000
8*10000-11*14000
= -74000
8*20000-11*4000
=116000
8*24000 = 192000
28000
8*10000-11*18000
= -118000
8*2000-11*8000
=72000
8*28000 = 224000
4. The order quantity to meet 70% demand is found by solving
P(X < K) =0.70
P(Z < (K-20000)/5102 ) = 0.70
(K-20000)/5102 = 0.5244
K = 20000 + 5102 * 0.5244 = 20000 + 2675 = 22675.
Order (K)
(K-20000)/5102
P(X > K)
15000
-0.98001
0.836458876
18000
-0.392
0.652472052
24000
0.784006
0.216518215
28000
1.568013
0.058439102
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