Gulf Coast Electronics is ready to award contracts for printing its annual repor
ID: 446082 • Letter: G
Question
Gulf Coast Electronics is ready to award contracts for printing its annual report. For the past several years, Johnson Printing and Lakeside Litho printed the four-color annual report. A new firm, Benson Printing, has inquired about the possibility of doing a portion of the printing. The quality and service level provided by Lakeside Litho has been extremely high; in fact, only 0.5% of their reports have been discarded because of quality problems. Johnson printing also has a historically high quality level, producing an average of only 1% unacceptable reports. Since Gulf Coast Electronics has had no experience with Benson Printing, they have estimated its defective rate to be 10%. Gulf Coast would like to determine how many reports should be printed by each firm to obtain 75,000 reports of acceptable quality. To ensure that Benson Printing will receive some of the contract, management has specified that the number of reports awarded to Benson Printing must be at least 10% of the volume given to Johnson Printing. In addition, the total volume assigned to Benson Printing, Johnson Printing, and Lakeside Litho should not exceed 30,000, 50,000, and 50,000 copies, respectively. Because of the long-term relationship that has developed with Lakeside Litho, management also has specified that at least 30,000 reports should be awarded to Lakeside Litho. The cost per copy is $2.45 for Benson Printing, $2.50 for Johnson Printing, and $2.75 for Lakeside Litho. Formulat and solve a linear program for determining how many copies should be assigned to each printing firm to minimize the total cost of obtaining 75,000 acceptable quality reports.
I am confused to what the constraints are for this problem. Thank you for your help
Explanation / Answer
Let x1=number of reports awarded to Benson Printing
x2=number of reports awarded to Johnson Printing
x3=number of reports awarded to Lakeside Litho
a. Minimize: 2.45x1+2.50x2+2.75x3
Subject to
x1+x2+x3<=75000
x1-0.10x2<=0
x3>=30000
x1<=30000
x2<=50000
x3<=50000
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