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x y P Chegg Study I Guided So wdhenke Bb Blackboard Learn Do Homework - william h x X C f https://www.mathxl.com/Student PlayerHomework.aspx?homeworkid=299973679&questionl; 8flushed =false& d=3387728&back;=D Assignm ents aspx%3f OM 4 a e = 1 Other bookmarks MyOMLab Homework: Chapter 6 homework (Capacity) william henkel 10/2/15 10:40 AM Overview Problem 6.4 Exercise Score: 3.75 of 25 pts Assignment Score: 35% (35 of 100 pts) 0 of 4 complete Macon Controls produces three different types of control units used to protect industrial equipment from overheating. Each of these units must be processed by a machine that Macon considers to be their process bottleneck. The plant operates on two S-hour shifts, 5- days per week, 52 weeks per year. The table below provides the time standards at the bottleneck, lot sizes, and demand forecasts for the three units. Because of demand uncertainties, the operations manager obtained three demand forecasts (pessimistic, expected, and optimistic). The manager believes that a 25 percent capacity cushion is best. Time Standard Demand Forecast Component (hr/unit) Processing Setup Lot Size Pessimistic Expected Optimistic 17,000 12,000 24.000 (hr/lot)(units/lot) 0.05 0.30 0.05 50 75 120 16,000 11,000 17,000 27,000 18,000 40.000 8.2 a. How many machines are required to meet minimum (Pessimistic) demand, expected demand, and maximum (Optimistic) demand? Enter your responses rounded up to the next whole number) Capacity Demand Forecast Requirement Pessimistic Expected Optimistic 3 machines 3 machines 5 machines b. How many machines are required if the operations manager decides to double lot sizes? Bnter your responses rounded up to the next whole number) Capacity Demand Forecast Requirement Pessimistic Expected Optimistic 2 machines 3 machines 4 machines c. If the operations manager has four machines and believes that the plant can reduce setup time by 25 percent through process improvement initiatives, does that plant have adequate capacity to meet all demand scenarios without increasing lot sizes? Enter your responses rounded up to the next whole number.) Enter your answer in the edit fields, then click Check Answer 2 parts r Clear All Check Answer Save 10:40 AM 10/2/2015Explanation / Answer
c)
Dp+(D/Q)s pessimistic + Dp+(D/Q)s Expected+ Dp+(D/Q)s Optimistic
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N(1-c/100)
= 7048 + 8302 + 13031 /( 4,160 *0.75 =3120 * 3=9360)
=28,381 / 9360
=3 machines
pessimistic
= 0.05(16,000)+(16,000 /50)1 + 0.30 (11,000 )+(11,000/75)4.20 + 0.05 (17,000)+(17,000/120)8.2
=(800 +320) + (3300+616) + (850+1162)
=7048
Expected Machines:
0.05(17,000)+(17,000/ 50)1 + 0.30(12,000)+(12,000 / 75)4.20+0.05(24,000)+(24,000/120)8.2
=(850 +340) + (3,600+672)+ (1200+1640)
= 8302
Optimistic
=0.05(27,000)+ (27,000/ 50)1 + 0.30((18,000) +(18,000/75)4.20+ 0.05(40,000)+(40,000/120)8.20
=(1350 +540) + (5400 +1008) + (2000+2733)
=13031
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