MGMT 3304-Summer 2018 lori bailey & 6/29/18 9:03 PM Homework: Chapter 13 Homewor
ID: 419311 • Letter: M
Question
MGMT 3304-Summer 2018 lori bailey & 6/29/18 9:03 PM Homework: Chapter 13 Homework Score: 3 of 6 pts & Problem4 Save 40f 4 (4 complete) ? HW Score: 75%, 9 of 12 pts E Question Help A larger and more modem main post office is to be constructed at a new location in Davis, California Growing suburbs caused a shift in the population density from where it was 40 years ago, when the current facility was built Annette Werk, the postmaster, asked her assistants to draw a grid map of the seven points where mail is picked up and delivered in bulk. The coordinates and trips per day to and from the seven mail source points and the current main post office, M, are shown in the following table. M will continue to act as a mail source point after relocation Mail Source Point Round trips per day x, y, Coordinates (miles) (6, 4) (12, 10) (9, 5) a. Calculate the center of gravity as a possible location for the new facility (Enter your responses rounded to the nearest whole number) The center of gravity "X"coordinate The center of gravity Y coordinate-11 b. Compare the load-distance scores for the location in part (a) and the current location, using rectilinear distance. (Round all intermediate calculations to the nearest whole number) The load-distance score to "M is (Enter your response as an integer) Enter your answer in the answer box and then click Check Answer Clear All remainingExplanation / Answer
The gravity X coordinates =(5*7+1*5+1*6+6*12+4*1+5*9+1*13+1*9)/(5+1+1+6+4+5+1+1) =7.88 =8
The gravity X coordinates =(5*17+1*11+1*4+6*10+4*15+5*5+1*3+1*5)/(5+1+1+6+4+5+1+1) =10.54 =11
Trip
(X,Y)
Distance = |XA– XB| + |YA– YB|
Load Distance = Distance* Demand
1
5
(7,17)
[(8-7)+(11-17)] =-5
=5*-5=-25
2
1
(5,11)
[(8-5)+(11-11)]=3
=1*3=3
3
1
(6,4)
[(8-6)+(11-4)] =9
=9*1=9
4
6
(12,10)
[(8-12)+(11-10)] =-3
=6*-3=-18
5
4
(1,15)
[(8-1)+(11-15)] =3
=4*3=12
6
5
(9,5)
[(8-9)+(11-5)]=5
=5*5=25
7
1
(13,3)
[(8-13)+(11-3)]=3
1*3=3
M
1
(9,5)
[(8-9)+(11-5)]=5
1*5=5
Load Distance Score =
14
Trip
(X,Y)
Distance = |XA– XB| + |YA– YB|
Load Distance = Distance* Demand
1
5
(7,17)
[(8-7)+(11-17)] =-5
=5*-5=-25
2
1
(5,11)
[(8-5)+(11-11)]=3
=1*3=3
3
1
(6,4)
[(8-6)+(11-4)] =9
=9*1=9
4
6
(12,10)
[(8-12)+(11-10)] =-3
=6*-3=-18
5
4
(1,15)
[(8-1)+(11-15)] =3
=4*3=12
6
5
(9,5)
[(8-9)+(11-5)]=5
=5*5=25
7
1
(13,3)
[(8-13)+(11-3)]=3
1*3=3
M
1
(9,5)
[(8-9)+(11-5)]=5
1*5=5
Load Distance Score =
14
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.