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rk for future following data. Resource suspension and engine me kilowatt-hours.

ID: 419074 • Letter: R

Question

rk for future following data. Resource suspension and engine me kilowatt-hours. Average la kits cost S1,000 each, and e What do you tell Mr. Muns T00 gallons at 35 per gallon 20 days at $50 per day Machine rental a) What is the labor productivity per dollar? b) What is the multifactor productivity? Px .1.8 Lillian Fok is president of Lakefront Manufacturing. a producer of bicycle tires. Fok makes 1,000 tires per day with the following resources: 1.11 boxes for fresh seafood pe ate three 8-hour shitis inste 400 hours per day @ $12.50 per hour Labor Raw material: 20,000 pounds per day $1 per pound Energy Capital costs $10,000 per day a) Calculete the company work rules and after the bi What is the percentage is $5,000 per day a) What is the labor productivity per labor-hour for these tires at 1.12 Charles Lacke Idaho. Because of its exce Lakefront Manufacturing? Lakefront Manufacturing? can reduce the energy bill by $1,000 per day without cutting b) What is the multifactor productivity for these tires at demand has aereased by J have their chose. Because of th c) What is the percent change in multifactor productivity if Fok added At a stalf nieetiog difterently so tha the ovens production or changing any other inputs? Px onc time This new proces

Explanation / Answer

a) Labor productivity = Output / Labor hours = 1000 / 400 = 2.5 units per labor hour

b) Total cost = (Labor cost + Material cost + Energy cost + Capital cost) = (400*12.5 + 20000*1 + 5000 + 10000) = $ 40000

Multifactor productivity = Output / Total cost = Output / (Labor cost + Material cost + Energy cost + Capital cost)

= 1000 / 40000  

= 0.025 units per dollar

c) New multifactor productivity (MFP) after cutting down $ 1000 = 1000/(40000-1000) = 0.0256 units per dollar

Percent Change in MFP = 100*(0.0256-0.025)/0.025 = 2.4 %