What is the minimum cost of crashing the following project that James Walters ma
ID: 410866 • Letter: W
Question
What is the minimum cost of crashing the following project that James Walters manages at Athabasca University by 4 days? ash Time Nor rash Cost Immediate Predecessor(s) Activity Time (days (days) Cost 200 S600 S750 $1,200 5600 650 $1,500 $1,650 By how many days should each activity be crashed to reduce the project completion time by 4 days? Fill in the table below. (Enter your responses as whole numbers.) Each Activity Should be Reduced BY days) Activity The total cost of crashing the project by 4 days is S(Enter your response as a whole number.)Explanation / Answer
The precedence diagram as follows :
A
B
C
D
E
The parallel paths and their corresponding durations as follows :
A-D = 5 + 5 = 10 days
B = 7 days
C- E = 4 + 7 = 11 days
Since C-E has the longest duration , it forms the Critical Path. Duration of critical path is same as normal duration of the project. Therefore, normal duration of the project will be 11 days
To reduce project completion time by 4 days, the revised project duration will be 7 days.
Project duration of 7 days will be achieved by:
By Crashing C by 1 day
By Crashing E by 3 days
By Crashing A by 1 day
By Crashing D by 2 days
Activity
Each activity should be reduced by ( Days)
A
1
B
0
C
1
D
2
E
3
Total cost of crashing the project by 4 days, $
= Crashing cost of A + Crashing cost of C + Crashing cost of D + Crashing cost of E
= Sum of ( Crash cost – Normal cost ) of all above activities
= (1000 – 800)+ ( 650 – 600) + ( 1500 – 750 ) + ( 1650 – 1200 )
= 200 + 50 + 750 + 450
= $1450
THE TOTAL COST OF CRASHING THE PROJECT BY 4 DAYS = $1450
A
B
C
D
E
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.