Specifications for a part for a DVD player state that the part should weigh betw

Question

Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A. Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A. What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.) How would I solve this? Please explain each step.

Explanation / Answer

z=(sample - population mean)/standard deviation
Which here means
z1= (24 - 24.5)/.2 = -2.5
z2= (25- 24.5)/.2 = 2.5

this means you dvd players will fall within plus or minus 2.5 standard deviations away from the mean.

Now using either a z-table in you book or you handy dandy ti-calculator you find the probability.

For the calculator:
P(meeting specs) = normalcdf(-2.5,2.5) <----- [2nd] [distr] [normalcdf]
you want P(of not meeting specs) so do 1-Ans

P(not meeting specs) = .0124

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.