Problem 1 - An undergraduate business student has purchased a laptop computer fo

Question

Problem 1 -

An undergraduate business student has purchased a laptop computer for use during exams. This laptop is perfectly reliable except for two parts: its microchip, which has a failure rate of one in every 15 hours of operation; and its battery, which has a failure rate of one in every 30 hours of operation. Assuming that a new battery has just been installed, what is the probability that the battery will perform reliably during a 2 hour exam?

Your Answer:

Problem 2 -

An undergraduate business student has purchased a laptop computer for use during exams. This laptop is perfectly reliable except for two parts: its microchip, which has a failure rate of one in every 30 hours of operation; and its battery, which has a failure rate of one in every 25 hours of operation. Assuming that a new battery has just been installed, what is the probability that the battery will FAIL during a 2 hourexam?

Your Answer:

Problem 3 -

An undergraduate business student has purchased a laptop computer for use during exams. This laptop is perfectly reliable except for two parts: its microchip, which has a failure rate of one in every 20 hours of operation; and its battery, which has a failure rate of one in every 20 hours of operation. Assuming that a new battery has just been installed, what is the probability that the LAPTOP will FAIL during a 1 hourexam?

Your Answer:

Explanation / Answer

1. probability of failure of microchip =1/15 ;

probability of failure of battery= 1/30;

overall failure probability in 1 hour = 1/15+1/30;

= 1/10

for 2 hours = 2/10 ;

probability that it will function properly for 2 hours = 1-2/10

=0.8;

2. probability of failure of microchip =1/30 ;

probability of failure of battery= 1/25;

overall failure probability in 1 hour = 1/25+1/30;

= 11/150

for 2 hours = 2*11/150 ;

probability that it will fail for 2 hours = 0.146 = 14.6%

3. probability of failure of microchip =1/20 ;

probability of failure of battery= 1/20;

overall failure probability in 1 hour = 1/20+1/20;

= 1/10;

for 1 hour = 1/10 ;

probability that it will fail for 2 hours = 0.1;

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