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HIsIury Bookmarks People Window Help 7 , 100% Rg. ! Tue Sep 4 9:37 PM Shi Jìnchu

ID: 395664 • Letter: H

Question

HIsIury Bookmarks People Window Help 7 , 100% Rg. ! Tue Sep 4 9:37 PM Shi Jìnchur Do Homework- Jinchun Shi Secure https://www.mathxl.com Student PlayerHomework.aspx?home workld-494660239&questionide17&flushed=true&cld-5131005&center in yes Operations Management-4231- MSOM 3101-007, TR 11:00 am -1 jinChun Shi | 9/4/18 9:37 PM Homework: Ch 7S - Capacity Mgmt Score: 0.25 of 1 pt & Problem S7.11 The three-station work cell llustrated in the figure below has a product that must go through one of the Save 11 of 20(17 complete) Score: 76%, 15.2 of 20 pts HY EQuestion Help two machines at station 1 (they are parallel) before proceeding to station 2 Capacity: 20 units/hr Station 1 Machine Station 2 Station 3 Station 1 Machine Capacity:Capacity: 12 units/hr 5 units/hr Capacity: 20 units/hr a) The bottleneck time of the system is 12 minutes per unit (enter your response as a whole number). b) Station 3 is the bottleneck station. c) The throughput time is minutes (enter your response as a whole number), Enter your answer in the answer box and then click Check Answer. Check Answer Clear All remaining

Explanation / Answer

time from production start to goods shipped is throughput time

here, throughput time = MAX(time at station 1 Machine A, time at station 2 Machine B) + time at station 2 + time at station 3

= MAX(1hr/20units,1hr/20units) + 1hr/12units + 1hr/5units

= MAX(3mins,3mins) + 5mins + 12mins

= 3 + 5 + 12 mins

= 20 mins