I already have the answer to the problem, I was just wondering if someone could

Question

I already have the answer to the problem, I was just wondering if someone could show me the work to get that answer. Thanks!

The lab where Kate works is very organized and keeps a database of all the primers ever ordered. One of these old primers will work for Kate?s next PCR experiment, along with the primer she just received. The only trouble is that this old primer dates back to the time when the lab used to dissolve the primers to a stock concentration of 1 ug/uL, whereas nowadays they are diluted to loo uM. So, in order to use this primer, Kate has to convert the units of the old stock to uM The molecular weight of the old primer is 6,789 g/mol. What is its concentration in uM, knowing that the concentration of the available stock is I ug/uL? A. l47 uM B. 2,057 uM C. 679 uM D. 6.79 x 10-3 uM E. I can?t calculate the answer unless I know the length of the primer

Explanation / Answer

Resuspend the primer in 100 ul of water or buffer and use the following calculation:

(XXg/mol100 ul) x (1000 pmol/nmol)= pmol/ul = uM

(6,789g/molmol/1 ug/uL) / (1000 pmol/nmol) = 679 pmol/ul =679 uM

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