In Python Define a recursive function accepts a number as a parameter and return

Q: In Python Define a recursive function accepts a number as a parameter and return

Following python code should do the job : def factorial_dictionary( N ): result = {}; if N == 0: return result; if N == 1: result[1] = 1; return result; result = factorial_dictionary( N - 1 ); result[N] = result[N-1]*N; return result; print( factorial_dictionary(1) ); print( factorial_dictionary(5) );

ID: 3935367 • Letter: I

Question

In Python

Define a recursive function accepts a number as a parameter and returns a dictionary. The dictionary should contain, as a key, every number from 1 to the given number. The corresponding value for each key should be the factorial of that number. You may not use any looping in your solution.

Parameter(s): 1. A single positive integer.

Return Value: A dictionary containing each integer and it’s corresponding factorial.

Example(s): >>> print(factorial_dictionary(1)) {1: 1}

>>> print(factorial_dictionary(5)) {1: 1, 2: 2, 3: 6, 4: 24, 5: 120}

Explanation / Answer

Following python code should do the job :

def factorial_dictionary( N ):
   result = {};
   if N == 0:
       return result;
   if N == 1:
       result[1] = 1;
       return result;

   result = factorial_dictionary( N - 1 );
   result[N] = result[N-1]*N;
   return result;

print( factorial_dictionary(1) );
print( factorial_dictionary(5) );

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In Python Define a recursive function accepts a number as a parameter and return

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