Iterative factorial: Finish the provided factorial function, so that it returns

Question

Iterative factorial: Finish the provided factorial function, so that it returns the value n!. Your code should use a forloop to compute the product 1 * 2 * 3 * ... * n. If you write the code carefully, you won't need a special case for when n equals 0.

Once implemented, uncomment the Program.assertEqual() statements at the bottom to verify that the test assertions pass.

var factorial = function(n) {
var result = 1;
for(var i = ......; i <= ..... ; ......) {
.......;
}

return result;
};

println("The value of 5! should be " + 5*4*3*2*1);
println("The value of 5! is " + factorial(5));
println("The value of 0! should be 1");
println("The value of 0! is " + factorial(0));

//Program.assertEqual(factorial(5), 120);
//Program.assertEqual(factorial(0), 1);

Explanation / Answer

function(n) {
var result = 1;
for(var i =1; i <=n ; i++) {
result=i*n;

}

Program.assertEqual(factorial(5), 120);
Program.assertEqual(factorial(0), 1);

println("The value of 5! should be " + 5*4*3*2*1);
println("The value of 5! is " + factorial(5));
println("The value of 0! should be 1");
println("The value of 0! is " + factorial(0));

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