Dr Peters Dr. Peters is a physician employed by a large primary care practice in

Question

Dr Peters Dr. Peters is a physician employed by a large primary care practice in Wynnewood, PA. The practice in which he works is open 260 days a year. Physicians have 30--minute appointment slots starting at 8am all the way up to 6pm. The practice is looking for improvement opportunities and wants to get a sense of the Overall People Effectiveness (OPE) of their physicians. The data collected so far suggests that - Dr. Peters spends 30 workdays a year on vacation. He also loses 2h of potential work time each day due to electronic medical record keeping (he blocks these 2 hours in his schedule, so no appointments are available during this time). Dr. Peters has a really busy schedule, so 75% of his appointments are booked. About half of the patients Dr. Peters sees are coming for their annual check-up. Such exam appointments are made a long time in advance. About one out of every six patients does not show up for his or her appointment. Though the appointment slots are 30 minutes per slot, Dr. Peters only spends, on average, 23 minutes with the patient (or doing work related to the patient after the patient has left the office). Of those 23 minutes, about 5 minutes could easily be done by one of Dr. Peters' assistants. Q1. How many patients does Dr. Peters see on a typical day when he is at work? Q2. What is his OPE? (Assume that his maximum availability is 260 days in a year)

Explanation / Answer

Q1. Dr Peter works from 8 AM to 6 PM

So total number of hours Dr Peter Works = A= 10 Hours

Amount of time lost on each day due to electronic medical record keeping = B = 2 hours

Net time in hours avalable to Dr Peter every day = C = A-B = 10-2 = 8 hours

Net time in minutes avalable to Dr Peter every day = D = 8 * 60 = 480 minutes

( There are 60 minutes in an hour)

Duration of appointment slot for patients = E = 30 minutes

Number of patients Dr Peter can see in a day = F = D/E = 480/30= 16

Since 75 % of appointments are fixed in advance so number of patients fixed in advance = G = F*75/100 = 16*75/100= 12

Half of these patients come for annual check ups which means number patients coming for regular check up = H = 12*50/100= 6

One out every six such patients do not turn up so patients visiting every day for annual check ups = I = 6-1 = 5 .

Now assuming all other half of patients who have prebooked their appointments turn up , number of booked patients seen by Dr Peter every day = J = 6 + 5 = 11

Number of unscheduled visits of patients every day = K= 25 % of F = 16*25/100= 4

Since Dr Peter is very busy we asume that he sees unscheduled visits every day of patients @ rate of 4 patients per day .

So total number of patients seen by Dr Peter every day = J + K = 11+ 4 = 15

Due to time constraint I will not be able to attempt Q2. but will certainly attempt if it comes back to me.

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