1. For each item below, assign a layer from the five-layer Internet Model that t

ID: 3917534 • Letter: 1

Question

1. For each item below, assign a layer from the five-layer Internet Model that the item primarily operates at.

Switch a. Layer 1

x.25 packet layer b. Layer 2

TCP C. Layer 3

ICMP D. Layer 4

UDP E. Layer 5

Repeater

AMI Line Code

SLIP

QUESTION 14 Match the terms with their most appropriate option A. Armival of multiple components of a signal take more time than the transmission of those components B. A minor impairment to a signal introduced when it is converted from analog form to digital form. C. Degradation of a signal that occurs when two consecutive signals overlap upon their arrival. D.A signal impairment that results from the reception of another intended transmission at the same time E. Signal degradation that might be due to electromagnetic emanations from such sources as firing spark Delay Distortion v Delay Spread Quantization Error v Impulse Noise Interference plugs or lightning strikes. QUESTION 15 Determine the best match for the items below A. False flag avoidance B. zero avoidance Bit Substitution Bit Robbing C. control signaling provision v Bit Stuffing QUESTION 16 Match the IP address and mask pairs with their types IP Address 202.0.18.63 using mask 255.255.255.192 IP address 123.45.67.89 using mask 255.255.255.248 IP Address 172.16.37.13 using mask 255.255.252.0 , IP Address 10.3.0.34 using mask 255255255240 A. A host on the 9th useable subnet. B. A subnet broadcast address. C. A subnet's network address D. First useable host on the subnet

Explanation / Answer

Question 1)

14)

15)

16)

IP Address 202.0.18.63 using mask 255.255.255.192 will give the address: 202.0.18.0/26. Therefore, is a B. A subnet broadcast address.

IP address 123.45.67.89 using mask 255.255.255.248 will give the address:123.45.67.88/29. Therefore, is a D. First useable host.

IP address 172.16.37.13 using mask 255.255.252.0 will give the address: 172.16.36.0/22. Therefore, the answer is A. A host on the 9th useable subnet.

IP address 10.3.0.34 using mask 255.255.255.240 will give the address:10.3.0.32/28, and therefore, 10.3.0.34 is actually, the second usable IP. (May be the answer is wrong, or it should be choice C)

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