MULTIPLE CHOICE (Analytical) -3 point each: Answer these on the back of the Scan

Question

MULTIPLE CHOICE (Analytical) -3 point each: Answer these on the back of the Scantron form beginning with number 51. For each of the following, select the one best choice and indicate it on your Scantron form. If no an swer is exactly correct, select the one that is closest to the actual answer. Marks made on this sheet will not be reflected in your grade in any way 51. The following are X, Y coordinates and (sales volume) of retail locations: Location 1) 3, 5 (20) Location 2) 6, 8 (30) Location 3) 2, 3 (15) Location 4) 4,5 (15) What are the coordinate of the geographic center of gravity, weighted by sales volume? A. 3.75, 5.25 B. 4.125, 5.75 C. 4,5 D. 6,8 E. 330, 460 52. The intensity of a process is 92% and the average service rate is 1300 units per minute. What is the average arrival rate at this process in units per minute? A. 1196 B. 1208 C. 1404 D. 1413 E. Cannot be determined. 53. An OSU junior has a 2.9 GPA in her first 75 credit hours. What average grade would she need in the 15 credit hours in which she's currently enrolled to get the 3.0 overall GPA she needs to land an interview for her dream job? A. 54-15(2.9) 75-15(29) B. C. 3.0 D. 15 75-15(2.9) E.

Explanation / Answer

51) x y sales given location1 3 5 20 location2 6 8 30 location3 2 3 15 location4 4 5 15 X=(x1*w1 + x2*w2 + x3*w3 + x4*w4 )/(w1+w2+w3+w4) Y=(y1*w1 + y2*w2 + y3*w3 + y4*w4 )/(w1+w2+w3+w4) X = (3*20 + 6*30 + 2*15 + 4*15)/(20+30+15+15) Y = (5*20 + 8*30 + 3*15 + 5*15)/(20+30+15+15) X=(330/80) Y=(460/80) X = 4.125 Y = 5.75 The answer is option B. (X,Y) = (4.125, 5.75) 52) Given process intensity is 92% Service rate is 1300/minute Process intensity = (Service rate/arrival rate)*100 Therfore Arrival rate = (service rate/process intensity)*100 Arrival rate = (1300/92)*100 Arrival rate = 1413 Answer is option D 1413 53) Given the student is with GPA of 2.9 with 75 credits The total credits she can accumulate is 90 credits and she wanted 3 GPA Therfore in the remaing 15 credits she needed 'X' GPA such that (X*15) + (2.9*75) = (3*90) X = (270-217.5)/15 X= 3.5 She needed 3.5 GPA in the remaining credits to take her overall GPA to 3 Answer is option D (270- (2.9*75))/15

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