C++11 (2 points) Given that an integer named x has been declared, which of the f

Question

C++11

(2 points) Given that an integer named x has been declared, which of the following lines of code will NOT compile? (a) const int ref x; (b) const int ref-5; (c) const int 8ref 5; (d) const int &&ref; x; (e) They will all compile (f) (b) & (d) (g) None of them will compile (2 points) Given that an integer named x has been declared, which of the following lines of code will NOT compile? (b) int &ref; 5; (c) int &&ref; 5; (d) int refx; (e) They will all compile (f) (b) & (d) (g) None of them will compile

Explanation / Answer

Ques 1.

Answer : (d) int &&ref = x

It is because we cannot bind a reference of type 'const int&&' to a of type 'int'

Ques 2.

Answer : (f) (b) & (d)

(b) It is because we cannot bind non-const reference of type 'int&' to a value of type 'int'

(d) It is because we cannot bind reference of type 'int&&' to a value of type 'int'

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