ANSWERS should be typed please! answer all parts of question please! any wrong/i

Question

ANSWERS should be typed please!

answer all parts of question please!

any wrong/incomplete/messy answer will be marked as spam, otherwise thumbs up :), if you are not an expert pleae leave the question.

Question # 2 A digitized video transmission carries a randomly mixed set of video packets. The occurrence statistics of the packets are designated in 10 groups. The video-transmission involves streaming of packets wherein the statistics of occurrence of bit rate may depend strongly on bit-rate values in consequent packets streamed and the RV is considered as of variable bit rate (VBR) type The number of occurrences of each group and the corresponding random value of the associated random bit rates in the packets (RVs) are as follows Events enumerated Bit rate (R) Video in Mbps: RV 6.4 5.9 0.6 6.2 5.76.1 6.35.7 5.6 0.2 packets Number of 80 | 60 | 50 | 40 | 50 | 60 | 75 40 30 20 occurrenceS Determine the following of the RV (Bit rate -R) Find the upper and lower bounds of the average performance of the RV State with reason the most appropriate mean value (AM HIM or GM) that describes the average performance of the bit rate I. ?. III. Find the expected mean, median, mode, variance and standard deviation IV. Plot the cumulative probability distribution (CDF) of the RV. Answer-hints: Median 5.8: ? = 1.9431

Explanation / Answer

SOLUTION:

a) Find the upper and lower bounds of the average performance of the RV:

Now, R - 48.7

ni = 505

Rini = 2237.5

b) From the above bit we had seen that the average performance of random variable is 4.87mbps.

c) Now find the mean, median, mode:

     Mean:

           Mean = Rini/ni

           We know that the values of Rini and ni

Rini = 2237.5

ni = 505

So, mean = 2237.5/505

Mean = 4.43

Median:

Median can be given as, now n = 505

The median will be average of 242th or 253th observation.

                       So, Median = (6.4 + 6.4) / 2

                                               = 128/2

                                   Median = 64

Mode:

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.