DQuestion 11 25 pts In an assembly process involving six distinct operations, it
ID: 390606 • Letter: D
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DQuestion 11 25 pts In an assembly process involving six distinct operations, it is necessary to produce 275 units per 8-h day. The measured operation times (in minutes) are as follows 1) 7.56 2) 4.25 3) 12.11 4) 1.58 5) 3.72 6) 8.44 a.) Determine the number of operators required at each work station for the given production requirement of 275 units/day, over an 8 hour day. b.) Determine which operation is the bottlneck C.) Determine the production line's daily output (for the 8 hour work day). Upload Choose a File o YExplanation / Answer
a. Time available per day = 60 minutes * 8 hours = 480 minutes
One unit of production will be needed every 480/275 = 1.75 minutes.
Operation
Processing time in minutes
Processing time /1.75
No. of Operators (whole number)
1
7.56
4.33
5
2
4.25
2.43
3
3
12.11
6.94
7
4
1.58
0.91
1
5
3.72
2.13
3
6
8.44
4.84
5
Total
24
b. Operation 3 in the bottleneck as it requires longest processing time.
c. First let’s calculate the capacity of each operation in following manner -
Operation
Processing time in minutes
No. of Operators (whole number)
Daily available time = (number of operation * 480 minutes)
Daily capacity = (Daily available time/ processing time)
1
7.56
5
2400
317
2
4.25
3
1440
339
3
12.11
7
3360
277
Bottleneck
4
1.58
1
480
304
5
3.72
3
1440
387
6
8.44
5
2400
284
Total
24
Operation 3 has the lowest daily capacity of 277 units. Therefore it is bottleneck of the process.
The production line’s daily output is equal to the bottleneck of the process. Therefore it is 277 units per day
Operation
Processing time in minutes
Processing time /1.75
No. of Operators (whole number)
1
7.56
4.33
5
2
4.25
2.43
3
3
12.11
6.94
7
4
1.58
0.91
1
5
3.72
2.13
3
6
8.44
4.84
5
Total
24
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