Obiecties In this lab, you will be given the network address 192.168.1.0\'24 to

Question

Obiecties In this lab, you will be given the network address 192.168.1.0'24 to subnet and provide the IP addressing for the network shown in the Topology section. Topology This topology contains 3 routers and 3 switches (See figure below). The networking has the following requirements 1- The Router1 LAN consists of 28 hosts 2-The Router2 LAN consists of 17 hosts 3- The Router3 LAN consists of 8 hosts Remember that the interfaces of network devices are also host IP addresses and are included in the above requirements. P.S. You do not have to create this topology with Packet Tracer 17 Hosts 8 Hosts 2 Hosts 2960 24TT 2960 24TT 2960 24TT Sw Fa0/0 Fao/D Fao/o S0jo 50/1 2620XM Routar1 2620XM Router2 2620XM Router3 Activity 1- Assign Subnets Start at the beginning of the 192.168.1.024 network. a- Assign the 1stavailable subnet to the Router1 LAN b- Assign the 2 available subnet to the Router2 LAN c- Assign the 3d available subnet to the Router3 LAN d- Assign the 4" available subnet to the WAN connection between Routerl and Router2 e- Assign the 5th available subnet to the WAN connection between Router2 and Router3

Explanation / Answer

we can create subnet on power of 2 raise to n so we need 5 subnet here but 5 is does not comes

in power of 2 , so next number we will take and that is 2^3 = 8 subnet

192.168.1.0/24 address is from class C and bydefault subnet mask of class c is 255.255.255.0

     Subnet             Mask              Host Range                  Broadcast Address
1) 192.168.1.0     255.255.255.224 192.168.1.1 to 192.168.1.30        192.168.1.31
2) 192.168.1.32    255.255.255.224 192.168.1.33 to 192.168.1.62        192.168.1.63
3) 192.168.1.64    255.255.255.224 192.168.1.65 to 192.168.1.94        192.168.1.95
4) 192.168.1.96    255.255.255.224 192.168.1.97 to 192.168.1.126       192.168.1.127
5) 192.168.1.128   255.255.255.224 192.168.1.129 to 192.168.1.158      192.168.1.159
6) 192.168.1.160   255.255.255.224 192.168.1.161 to 192.168.1.190      192.168.1.191
7) 192.168.1.192   255.255.255.224 192.168.1.193 to 192.168.1.222      192.168.1.223
8) 192.168.1.224   255.255.255.224 192.168.1.225 to 192.168.1.254      192.168.1.255

each subnet above will give us 62 hosts so we will assign to each router lan

1-Assign subnets
*****************

For router 1 (27 hosts + 1 router = 28)
192.168.1.0     255.255.255.224 192.168.1.1 to 192.168.1.30        192.168.1.31

For router 2 (16 hosts + 1 router = 17)
192.168.1.32    255.255.255.224 192.168.1.33 to 192.168.1.62        192.168.1.63

For router 3 (7 hosts + 1 router = 8)
192.168.1.64   255.255.255.224 192.168.1.65 to 192.168.1.94         192.168.1.95

4th WAN Router 1 & 2
192.168.1.96    255.255.255.224 192.168.1.97 to 192.168.1.126       192.168.1.127

5th WAN Router 2 & 3
192.168.1.128   255.255.255.224 192.168.1.129 to 192.168.1.158      192.168.1.159

6th 7th 8th subnet will be unused as its not needed

2- Assign IP to router 1
***************************
Fa0/0   192.168.1.1    255.255.255.224
S0/0    192.168.1.96   255.255.255.224
S0/0    192.168.1.126   255.255.255.224

3-Assign IP Addresses to router 2
*********************************
Fa0/0   192.168.1.35   255.255.255.224
S0/0    192.168.1.129   255.255.255.224
S0/1    192.168.1.158   255.255.255.224

4-Assign IP addresses to router 3
**********************************
Fa0/0   192.168.1.65   255.255.255.224
S0/0    192.168.1.130 255.255.255.224

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