c++ language E 14.8 Memory Locations for Exercise 11 Variable: ptNum Address: 50
ID: 3905166 • Letter: C
Question
c++ language
E 14.8 Memory Locations for Exercise 11 Variable: ptNum Address: 500 Variable: amtAddr Address: 564 Variable: zAddr Address: 8024 Variable: numAddr Address: 10132 20492 18938 Variable: ptDay . Address: 14862 Variable: ptYr Address: 15010 694 Variable: years Address: 694 Variable: m Address: 8096 Variable: amt Address: 16256 Variable: firstnum Address: 18938 154 Variable: balance Address: 20492 Variable: k Address: 24606 11. For the variables and addresses illustrated in Figure 14.8, fill in the appropriat as determined by the following statements: a. ptNamm b. amtAddramt : d. knumAddr ptYr1987Explanation / Answer
11)
a) ptNum=&m;
since the address of m=8096
so ptNum=8096;
b)
amtAddr(address=564)=&amt;
Therefore amtAddr=16256
c)
*zAddr=25;
*20492 (address of balance) so value at 20492=25
so balance=25
d)
k=*numAddr=*18938(18938=address of firstnum)=154( value at 18938)
so k=154
e)
ptDay=zAddr
ptDay=20492
f)
*ptYr=1987;
*694 (694=address of years) so years contains the value 1987
g)
*amtAddr=*numAddr
*amtAddr=*18938=154
*amtAddr=154
*16256=154
so amt contains the value 154
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