import java.util.Scanner; public class Fibonacci { public static void main(Strin

Question

import java.util.Scanner;

public class Fibonacci {

public static void main(String[] args) {

  int x;
  @SuppressWarnings("resource")
  Scanner limitEntery = new Scanner(System.in);

  System.out.print("Enter x under 100: ");

  x = limitEntery.nextInt();
  if(x>=92)
  {
   System.out.println("Sorry the limit is 91!!!");
  }
  else {
   long[] series = new long[x];

   series[0] = 0;
   series[1] = 1;

   for(int i=2; i < x; i++){
    series[i] = series[i-1] + series[i-2];
   }

   System.out.println("Fibonacci Series are up to " + x);
   for(int i=0; i< x; i++){
    System.out.print(series[i] + " ");
   }
   for(int i=x-1; i >= 0; i--){
    System.out.print(series[i] + " ");
   }
  }
}
}

I have a code, but I also want to get the answer backward.

So there will be 2 answers, the first one is the forward and the backward.

Explanation / Answer

Fibonacci.java

import java.util.Scanner;

public class Fibonacci {

public static void main(String[] args) {

int x;
@SuppressWarnings("resource")
Scanner limitEntery = new Scanner(System.in);

System.out.print("Enter x under 100: ");

x = limitEntery.nextInt();
if(x>=92)
{
System.out.println("Sorry the limit is 91!!!");
}
else {
long[] series = new long[x];

series[0] = 0;
series[1] = 1;

for(int i=2; i < x; i++){
series[i] = series[i-1] + series[i-2];
}

System.out.println("Fibonacci Series are up to " + x);
for(int i=0; i< x; i++){
System.out.print(series[i] + " ");
}
System.out.println();
for(int i=x-1; i >= 0; i--){
System.out.print(series[i] + " ");
}
}
}
}

Output:

Enter x under 100: 10
Fibonacci Series are up to 10
0 1 1 2 3 5 8 13 21 34
34 21 13 8 5 3 2 1 1 0

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