A tennis player swings her 1000 g racket with a speed of 10.0m/s . She hits a 60

Question

A tennis player swings her 1000 g racket with a speed of 10.0m/s . She hits a 60 g tennis ball that was approaching her at a speed of 18.0m/s . The ball rebounds at 36.0m/s. How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision. Express your answer with the appropriate units. If the tennis ball and racket are in contact for 14.0ms . what is the average force that the racket exerts on the ball? Express your answer with the appropriate units.

Explanation / Answer

Part A)

Conservation of momentum

mv + mv = mv' + mv'

(1)(10) + (.06)(-18) = 1(v') + (.06)(36)

v' = 6.76 m/s

Part B)
Apply the impulse momentum theorem

Ft = m(delta v)

F = (.06)(36 - (-18))/14 X 10^-3

F = 231 N

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