%3Cp%3E%3Cb%3E%3Cspan%20class%3D%22c1%22%3EFind%20the%20slop%20of%20the%20line%2
ID: 3900578 • Letter: #
Question
%3Cp%3E%3Cb%3E%3Cspan%20class%3D%22c1%22%3EFind%20the%20slop%20of%20the%20line%20pertaining%20to%20data%0Afrom%20the%20100%3C%2Fspan%3E%3C%2Fb%3E%3Cspan%20class%3D%22c2%22%3E%3Cimg%20width%3D%2211%22%20height%3D%2216%22%0Aid%3D%22_x0000_i1025%22%20src%3D%0A%22file%3A%2F%2Flocalhost%2FUsers%2Fmohammedalqudimi%2FLibrary%2FCaches%2FTemporaryItems%2Fmsoclip%2F0%2Fclip_image001.png%22%20%2F%3E%3C%2Fspan%3E%0A%3Cb%3E%3Cspan%20class%3D%22c3%22%3Etubular%20resistor%20and%20compare%20it%20to%20its%20rated%0Aresistance.%3C%2Fspan%3E%3C%2Fb%3E%3C%2Fp%3E%0A%3Cp%20class%3D%22c1%22%3E%3Cspan%20class%3D%22c3%22%3E%20%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c5%22%3Ei%20found%20the%20slope%20from%26nbsp%3B%3Cspan%20class%3D%22c4%22%3Ey%0A%3D%20104.94x%20-%202.4637%20to%20be%20104.94%20...%26nbsp%3B%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c5%22%3E%3Cspan%20class%3D%22c4%22%3E%3Cbr%20%2F%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c5%22%3E%3Cspan%20class%3D%22c4%22%3EQuestion%201%20%3A%20whats%20the%20rated%0Aresistance%20for%20the%20100%20ohms%20resistor%20and%20how%20can%20i%20get%20it%20so%20i%20can%0Acompare%20it%20with%20the%20slope%26nbsp%3B%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c5%22%3E%3Cspan%20class%3D%22c4%22%3EQuestion%202%3A%20Whats%20the%20accuracy%0Aof%20your%20measurements%20of%20R%20based%20on%20question%0A1%26nbsp%3B%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fp%3E%0AExplanation / Answer
your equation is of the form
y=mx+c where y is voltage and x current , and slope m is resistance
(by ohms law V=IR so y=mx the extra C is coming in equation because of experimental errors )
so
1] so resistance is 104.94
2] percentage error = [104.94-100]*100/100=4.94 %
so percentage accuracy = 100-4.94=95.06 %
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