please explain and show work Lens 1 is a converging lens with a focal length of

Question

please explain and show work

Lens 1 is a converging lens with a focal length of 60 cm. An object 5 cm tall is placed 30 cm to its left. Lens 2, which is a diverging lens with a focal length of 15 cm, lies 40 cm to the right of lens 1. (1) Describe the position and properties (virtual or real, inverted or upright of the final image. (2) What is the lateral magnification? (3) How tall is the final image? (4) Draw on the diagram il, p2, and 12 with the orientation (inverted or upright and size (smaller or bigger than pl). Lens 2

Explanation / Answer

do first lens

1/30 + 1/i = 1/60

1/i = 1/60 - 1/30 = 1/60 - 2/60 = -1/60

so i = -60

m1 = -i/o = 60/30 = 2

treat this as a second object

o = 100

1/100 + 1/i = 1/-15

i = -13.04

virtual and 13.04 cm to the left o the diverging lens

m2 = 13.04/100

2) M = m1*m2 = 2*13.04/100= 0.26

3) h' = 5*0.26 = 1.3 cm

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