2.) Consider an RL series circuit. R is still 881 ? and you measure L to be 773

Question

2.) Consider an RL series circuit. R is still 881 ? and you measure L to be 773 mH. You again set the signal generator output to produce a sinusouidal output with an amplitude of 1.85 V.

i) At what frequency will XL equal R?

ii) What will the voltage across the inductor be at this frequency?

We use the compound signal described above.

iii) Answer the following: What will the ratio of the amplitude of the voltage across the resistor due to the 49.1 Hz component of the signal to that of the 779 Hz component?

Explanation / Answer

R=881 ohm

For f=49.1 Hz

Xl1=2*3.14*49.1*773X10^-3=238.47 ohm

Vr1=881*1.85/912.7=1.786V

for f=779 hz

Xl2=2*3.14*779*773X10^-3=3783.52 ohm

Vr2=881*1.85/3884.74=0.419V

Ratio=vr1/vr2=1.786/0.419=4.257

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