%3Cp%3E%3Cspan%20class%3D%22c1%22%3EFind%20the%20ratio%20of%20speeds%20of%20a%3C

Question

%3Cp%3E%3Cspan%20class%3D%22c1%22%3EFind%20the%20ratio%20of%20speeds%20of%20a%3C%2Fspan%3E%0Aproton%3Cspan%20class%3D%22c1%22%3E%20and%20an%26nbsp%3B%3C%2Fspan%3Ealpha%0Aparticle%3Cspan%20class%3D%22c1%22%3E%26nbsp%3Baccelerated%20through%20the%20same%0Avoltage%2C%20assuming%20nonrelativistic%20final%20speeds.%20Take%20the%20mass%20of%0Athe%20alpha%20particle%20to%20be%26nbsp%3B%3C%2Fspan%3E%3Cspan%20class%3D%0A%22nobr%20c4%22%3E6.64%26nbsp%3B%3Cspan%20class%3D%0A%22c2%22%3E%3F%3C%2Fspan%3E%26nbsp%3B10%3Csup%3E%3Cspan%20class%3D%0A%22c3%22%3E%3F%3C%2Fspan%3E27%3C%2Fsup%3E%26nbsp%3Bkg.%3C%2Fspan%3E%3Cbr%20class%3D%22c5%22%20%2F%3E%3C%2Fp%3E%0A%3Cdiv%20class%3D%22watexline%22%3E%0A%3Ctable%20class%3D%22watexfraction%20c8%22%3E%0A%3Ctbody%3E%0A%3Ctr%3E%0A%3Ctd%20class%3D%22watexnumerator%20c6%22%3Eproton%26nbsp%3Bspeed%3C%2Ftd%3E%0A%3C%2Ftr%3E%0A%3Ctr%3E%0A%3Ctd%20class%3D%22watexdenominator%20c7%22%3Ealpha%20particle%26nbsp%3Bspeed%3C%2Ftd%3E%0A%3C%2Ftr%3E%0A%3C%2Ftbody%3E%0A%3C%2Ftable%3E%0A%3C%2Fdiv%3E%0A%3Cp%3E%3Cspan%20class%3D%22c1%22%3E%26nbsp%3B%3D%26nbsp%3B%3C%2Fspan%3E%3Cspan%20class%3D%0A%22qTextField%20c1%22%3E%3Cinput%20type%3D%22text%22%20name%3D%22RN_2447567_5_0_2453849%22%0Avalue%3D%22.012%22%20size%3D%2210%22%20id%3D%22RN_2447567_5_0_2453849%22%20dir%3D%22ltr%22%20class%3D%0A%22c9%22%20%2F%3E%3C%2Fspan%3E%3Cspan%20class%3D%22c1%22%3E%26nbsp%3B%3C%2Fspan%3E%3Cspan%20id%3D%0A%22RN_2447567_5_0_2453849_mark%22%20class%3D%0A%22waMark%20single%20mIncorrect%20c13%22%3E%3Cspan%20class%3D%0A%22badgeWrap%20c12%22%3E%3Cspan%20class%3D%22badge%20container%20c11%22%3E%3Cimg%20src%3D%0A%22http%3A%2F%2Fwww.webassign.net%2Fstatic%2Fwacache76dc611d6ebaafc66cc0879c71b5db5c%2Fimg%2Fquestions%2FmarkSprite.png%22%0Aalt%3D%22Incorrect%3A%20Your%20answer%20is%20incorrect.%22%20title%3D%0A%22Your%20answer%20is%20incorrect.%22%20class%3D%0A%22c10%22%20%2F%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3Cspan%20class%3D%0A%22c1%22%3E%26nbsp%3B%3C%2Fspan%3E%3Cbr%20class%3D%22c5%22%20%2F%3E%0AHow%20is%20the%20change%20in%20electric%20potential%20energy%20related%20to%20the%0Achange%20in%20kinetic%20energy%3F%3C%2Fp%3E%0A%3Cp%3E%3Cspan%20class%3D%22c14%22%3EPLEASE%20SHOW%20YOUR%20WORK%20PLEASE%26nbsp%3B%3C%2Fspan%3E%3C%2Fp%3E%0A

Explanation / Answer

potential energy = qV

kinetic energy = 1/2 * m * V^2

conserving them

q(p)*m(alpha) / q(a) m(p) = [Vp/Va]^2

vp/va=1.414

q(a)=2q(p)

m(p)=1.67262178

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