A rectangular loop of wire with sides 0.251 and 0.537 m lies in a plane perpendi

Question

A rectangular loop of wire with sides 0.251 and 0.537 m lies in a plane perpendicular to a constant magnetic field (see part a of the drawing). The magnetic field has a magnitude of 0.575 T and is directed parallel to the normal of the loop's surface. In a time of 0.187 s, one-half of the loop is then folded back onto the other half, as indicated in part b of the drawing. Determine the magnitude of the average emf induced in the loop.

- Most importantly: Can you show your work and how you arrived to the solution.

Explanation / Answer

induced emf =rate of change of magnetic flux

magnetic flux=magetic field.area (dot product of magnetic field and area vecor)

therefore induced emf=magnetic field*changed arae/time=0.575*0.251*0.537/0.187=0.414445volts

so the magnitude of average emf induced inthe loop =0.414445volts

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