A flashlight bulb carries a current of 0.16 \\({\ m A}\\) for 79 \\({\ m s}\\) .

Question

A flashlight bulb carries a current of 0.16({ m A}) for 79({ m s}).

Part A How much charge flows through the bulb in this time?
(Delta Q) =
( m C)
Part B How many electrons? A flashlight bulb carries a current of 0.16({ m A}) for 79({ m s}).

A flashlight bulb carries a current of 0.16({ m A}) for 79({ m s}).

A flashlight bulb carries a current of 0.16({ m A}) for 79({ m s}).

Part A How much charge flows through the bulb in this time?
(Delta Q) =
( m C)
Part A How much charge flows through the bulb in this time?
(Delta Q) =
( m C)
(Delta Q) =
( m C) (Delta Q) =
( m C)
Part B How many electrons? (Delta Q) =
( m C)

Explanation / Answer

i = Q/t

So, Q = i.t = 0.16 * 79 = 12.64 C

No of electrons = 12.64 / 1.6*10^-19 = 7.9 * 10^19 electrons

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.