public static String mystery (String s) { char []temp = new char[1]; if (s.equal

ID: 3898313 • Letter: P

Question

public static String mystery (String s)

{

char []temp = new char[1];

if (s.equals("")) return"";

if("aeiouAEIOU".indexOf(s.charAt(0)) != -1)

{

temp[0]=s.charAt(0);

return new String(temp) + mystery(s.substring(1));

}

else return "" + mystery(s.substring(1));

}

a) show all the call to the function and what each one returns to its predecessor?

String result = mystery ("Omar");

Call#

1. mystery("Omar") returns ____ to result

2. mystery("___") returns _____ to Call ____

3. mystery ("__") returns ____ to Call #2.

4. mystery ("__") returns ____ to Call ___

5. mystery ("") returns "" to Call#4

b) Describe what the mystery method accomplishes

Answer a) The value of result is "Oa"

The calls and values returned are

1. mystery("Omar") returns "Oa" to result

2. mystery("mar") returns "a" to Call #1

3. mystery ("ar") returns "a" to Call #2.

4. mystery ("r") returns "" to Call #3

5. mystery ("") returns "" to Call#4

===============
Answer to b)
mystery function retains only vowels and removes all other characters from the input string s

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