hi any one help me to solve these A frog leaps to catch an insect. If the frog\'

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hi any one help me to solve these

A frog leaps to catch an insect. If the frog's jump was at 60.0 degree off the ground and its initial velocity was 2.3 m/s, what is the highest point of its trajectory? 0.13 m 0.2 m 9.2 m 0.4 m A rescue plane flying horizontally at 82.5 m/s spots a survivor in the ocean 73 m directly below and releases an emergency kit with a parachute. Because of the shape of the parachute, it experiences insignificant horizontal air resistance. If the kit descends with a constant vertical acceleration of 7.08 m/s2, how far away from the survivor will it hit the water? 265 m 318m 1.7 km 375 m A food processor spins at a constant rate of 2400 rpm. If the blade's diameter is 8.6 cm, what is the acceleration at the tip of the blade? 21.61 m/s2 2.716 times 105 m/s2 2716 m/s2 2161 m/s2 A driver in a 1000.0 kg car traveling at 26 m/s slams on the brakes and skids to a stop. If the coefficient of friction between the tires and the road is 0.80, how long will the skid marks be? 43 m 54 m 40 m 34 m A 6.0 kg box slides down an inclined plane that makes an angle of 39 degree with the horizontal. If the coefficient of kinetic friction is 0.14, at what rate does the box accelerate down the slope? 5.6 m/s2 5.1 m/s2 6.0 m/s2 6.7 m/s2 A 65 kg ice skater pushes off his partner and accelerates backwards at 1.3 m/s2. If the partner accelerates in the opposite direction at 2.1m/s2, what is the mass of the other skater? Assume that frictional forces are negligible. 43 kg 105 kg 40 kg 35 kg A 78 kg cosmonaut seats in a Soyuz rocket. Shortly after take-off, the rocket's acceleration peaks at 38 m/s straight up. What is the cosmonaut's apparent weight? 2964 N 3729 N 2199 N 765 Two blocks are on a turntable. If the second is at three times the radius of the first, what is the ratio of its centripetal acceleration to that of the first block? 3:1 1:9 1:3 9:1

Explanation / Answer

1. vy^2 = v0y^2 + 2 a y

max height when vy = 0

so 0^2 = (2.3*sin(60))^2 - 2*9.81*y
y=0.2 m

2. y direction
y = y0 + v0y t + 1/2 a t^2

0 = 73 + 0*t - 0.5*7.08*t^2

t = 4.54 s

x = 4.54*82.5 = 375 m so d)

3) a = w^2 r = (2400*2*pi/60)^20.086 = 2716 so c)

4) a = F/m = u m g/m = u g

v^2 = v0^2 + 2 a x

0 = 26^2 -2*0.8*9.81*x
x= 43 m so a)

5) sum forces in the y
m g sin theta - friction = ma
friction = u N = u m g cos theta

a = g sin theta - u g cos theta = 9.81*sin(39) - 0.14*9.81*cos(39) = 5.1

so b)

8) a = w^2 r
so three times the radius means 3:1
so a)

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