A sled rider at a speed of 4.0 m/s along an horizontal stretch. The snow exercis

Question

A sled rider at a speed of 4.0 m/s along an horizontal stretch. The snow exercises a kinetic friction on the sled.

So the sled slows down and eventually stops. What is the displacement X of the sled?

In the Olympic Games at Sochi, a sled and its rider are moving at a speed of 4.0 m/s along a horizontal stretch of snow. The snow exercises a kinetic frictional force on the runner of the sled, so the sled slows down and eventually comes to a stop. The coefficient of kinetic friction is 0.050. What is the displacement x of the sled?

Explanation / Answer

friction force = mg*u = m*9.8*0.05

thus de-acceleration = 9.8*0.05

v ^2 = u^2 -2ad

=> 0 = 4^2 - 2*9.8*0.05*d

=> d = 16.326530612 m

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