plz do it step by step U.S. (1:35) Tue 4:48 PM Q. Preview File Edit View Go Tool

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plz do it step by step

U.S. (1:35) Tue 4:48 PM Q. Preview File Edit View Go Tools Bookmarks Window Help hw6+spring.pdf (page 1 of 2 Sidebar Search Next Question 4: Consider two concentric cylindrical shells, one of radius R1, and the other of radius R2 R1. The length hw6+spring. pdf of the shells is L, such that L R1, so we can assume that E Er(r) (cylindrical symmetry). Assume the inner shell has a total charge +Q, the outer shell total charge -Q. a) Find E(r) using Gauss's law. Hint: Use a Gaussian surface that is a cylindrical shell of radius r, R1

Explanation / Answer

Flux = Q / e     where e = the permittivity constant

Flux = 2 * pi * R1 * L * o / e    where o = surface charge density

(Since Q = o * A)

Flux = E * A = E * 2 * pi * r * L   flux thru cylinder of radius r

(A here = area of Gaussian cylinder of radius r)

E = R1 * o / (e * r)    electric field at distance R - combining equations

V = R1 * o / e * (integral of dr / r)

V = R1 * o / e * ln (R2 / R1)

Since C = Q / V and Q = 2 * pi * R1 * L * o

C = 2 * pi * L * e / ln (R2 / R1)

C depends only the geometry

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