pls do it Simplify the following circuit to a single capacitor Ceq and calculate

Question

pls do it

Simplify the following circuit to a single capacitor Ceq and calculate the value of Ceq in terms of C1...C6 A parallel-plate capacitor has square plates of edge lengths 1 cm, and a plate separation of 1 mm. It is connected to a 12V battery What is the capacitance and the energy stored inside the capacitor? The battery is disconnected, and you insert a dielectric material, e=2 by hand between the plates. What is the new energy stored in the capacitor? Did you do work in putting the dielectric?

Explanation / Answer

Q1. Ceq= C1+C2+C3+C4+(C5||C6)

Q2. a. Capacitance = A*epsilon/d = 0.8854 pF

Energy= 0.5*C*V^2 = 6.374 * 10^-11 J

b. New Energy = Old Energy/epsilon = 3.187* 10^-11 J [ epsilon=2]

Yes, we did work while putting the dielectric as final energy is lower than initial energy.

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