Scuba divers are planning a dive to a sunken shipwreck at the bottom of a lake.

Question

Scuba divers are planning a dive to a sunken shipwreck at the bottom of a lake. They use high powered spotlights to locate their dive site. A spotlight shines directly from the edge of their support vessel and illuminates the wreck when it is aimed 60 degrees relative to the vertical. The light sits 3 m above the waterline and the wreck 500 m below the surface.

a) if you ignore the refraction of the light in the water, what is the perceived horizontal distance between the light and the wreck?
b) accounding for refraction, what is the actual horizontal distance between the light and the wreck?

c) given the above answers, in your opinion, is it important to account for refreaction in locating the correct location for this dive? explain your reasoning

SHOW WORK PLEASE

the waterline, and the wreck is 500m below the surface, If You ignore the refraction of the light in the water, what is the horizontal distance between the light and the wreck? Accounting for refraction, what is the actual horizontal distance and the wreck? refraction in locating the correct location for this diva? Explain clearly. om a mystery material into water undergoes total internal the index of refraction of the mystery material? Using material.

Explanation / Answer

1.

.503*tan(60 deg)

= 871.22 m

b) sin(60deg) = 1.33*sin(theta)

theta = 40.628 deg

distance = 500*tan(40.628 deg)+3tan(60)

=434.175 m

c) Yes, as it can be seen from result that actual and apperent distances differ by a very large value so it important to account for refreaction in locating the correct location

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.