helkps show soln s The figure shows an iron ball suspended by thread of negligib
ID: 3896785 • Letter: H
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helkps show soln
s
The figure shows an iron ball suspended by thread of negligible mass from an upright cylinder that floats partially submerged in water. The cylinder has a height of 5.80 cm, a face area of 13.0 cm2 on the top and bottom, and a density of 0.295 g/cm3, and 1.70 cm of its height is above the water surface. The water has a density of 1000 kg/m3, and the iron has a density of 7900 kg/m3. What is the radius r of the iron ball? The water flowing through a 2.0 cm (inside diameter) pipe flows out through three 1.4 cm pipes, (a) If the flow rates in the three smaller pipes are 25, 19, and 10 L/min, what is the flow rate in the 2.0 cm pipe? What is the ratio of the speed of water in the 2.0 cm pipe to that in the pipe carrying 25 A venturi meter is used to measure the flow speed of a fluid in a pipe. The meter is connected between two sections of the pipe (the figure); the cross-sectional area A of the entrance and exit of the meter matches the pipe's cross-sectional area. Between the entrance and exit, the fluid flows from the pipe with speed V and then through a narrow "throat" of cross-sectional area a with speed v. A manometer connects the wider portion of the meter to the narrower portion. The change in the fluid's speed is accompanied by a change Ap in the fluid's pressure, which causes a height difference h of the liquid in the two arms of the manometer. (Here Ap means pressure in the throat minus pressure in the pipe.) Suppose that the fluid is fresh water, that the cross-sectional areas are 59 cm2 in the pipe and 28 cm2 in the throat, and that the pressure is 60 kPa in the pipe and 41 kPa in the throat. What is the rate of water flow in cubic meters per second?Explanation / Answer
using the bernaouli's principle :
60000 + 500v1^2 = 41000 + 500v2^2
and 59v1 = 28v2 (equation of contunuity)
thus 2.11v1 = v2
thus the v1 = 3.32cm/sec
thus the flow rate = 3.32 x 59 = 196cm^3/sec or
Q = 11.76 L/min
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