on average 2 customers per hour use the public telephone in the sheriff\'s deten
ID: 389551 • Letter: O
Question
on average 2 customers per hour use the public telephone in the sheriff's detention area, and this use has a Poisson distribution. The length of the phone call follows exponential distribution with a mean of 6 minutes. The sheriff will install a second telephone booth when an arrival can expect to wait 3 minutes or longer for the phone. What is the arrival rate that justifies a second telephone booth?
Question 3 options:
a)
none of the answers
b)
4 per hour
c)
2.5 per hour
d)
3.33 per hour
e)
8 per hour
a)
none of the answers
b)
4 per hour
c)
2.5 per hour
d)
3.33 per hour
e)
8 per hour
Explanation / Answer
Arrival rate (A) = 2 per hour
Service rate (S) = 6 min or 60/6 = 10 per hour
Lq = A/(S*(S-A))
For Lq = 3/60 hour and S = 10,
3/60 = A/(10*(10-A))
0.5*(10-A) = A
3A = 10
A = 3.33 per hour
Ans D
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