and the battery emfs are E1 = 1.5 V and E2 = 3.0 V. I have answered a,b,c. Just

Question

and the battery emfs are E1 = 1.5 V and E2 = 3.0 V.

I have answered a,b,c. Just need d.

(a) Let I1 be the branch current though R1, I2 be the branch current through R2, and I3 be the branch current through R3. Write Kirchhoff's loop rule relation for a loop that travels through battery 1, resistor 1, and resistor 3. (Use a clockwise current loop when entering your answer. Use any variable or symbol stated above as necessary.)

E1-I1R1-I3R3=0

(b) Write Kirchhoff's loop rule relation for a loop that travels through battery 2, resistor 2, and resistor 3. (Use a clockwise current loop when entering your answer. Use any variable or symbol stated above as necessary.)

-E2+I3R3-I2R2=o

(c) Apply Kirchhoff's junction rule to the junction at A to get a relation between the three branch currents. (Use any variable or symbol stated above as necessary.)

I1=I2+I3

(d) You should now have three equations and three unknowns (I1, I2, and I3). Solve for the three branch currents.

I1?

I2?

I3?

Explanation / Answer

1.5 - 2200(i2+i3) - 1500(i2)- 3 = 0

-1.5 = 3700i2+2200i3

-3 +4300i3 -1500i2 = 0

1500i2 - 4300i3 = -3

solving both

i2 = -0.679 mA

i3 = 0.461 mA

i1 = -0.218m A

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