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My apologies for not offering much points. I am low on points right now. I need

ID: 3894576 • Letter: M

Question

My apologies for not offering much points. I am low on points right now. I need to save points for other problems to post since next test is coming on next week. Thanks for your understanding!



Two forces, of magnitudes F1 and F2, act in opposite directions on a block, which sits atop a frictionless surface. (Figure 1) Initially, the center of the block is at position xi. At some later time, the block has moved to the right, so that its center is at position xf, where xf>xi




Part A Find the work W1 done on the block by the force of magnitude F1 as the block moves from xi to xf. Express your answer in terms of some or all of the variables given in the problem introduction. Part Find the work W2 done by the force of magnitude F2 as the block moves from xi to xf. Express your answer in terms of some or all of the variables given in the problem introduction. Part C What is the net work Wnet done on the block by the two forces? Part D Imagine that the two forces are equal in magnitude. F1 = F2. and that there are no other horizontal forces acting on the block. Determine the change Kf - Ki in the kinetic energy of the block as it moves from xi to xf.

Explanation / Answer

W.D= Fs


part a

W.D= F1 (Xf-Xi) N-m


part B

W.D= F1 (Xi-Xf) N-m


part C

Net W.D= (F1-F2)*(Xf-Xi) N-m


Part D

when Both force r equal then


Net W.D. =Zero   

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