My apologies for not offering much points. I am low on points right now. I need
ID: 3894576 • Letter: M
Question
My apologies for not offering much points. I am low on points right now. I need to save points for other problems to post since next test is coming on next week. Thanks for your understanding!
Two forces, of magnitudes F1 and F2, act in opposite directions on a block, which sits atop a frictionless surface. (Figure 1) Initially, the center of the block is at position xi. At some later time, the block has moved to the right, so that its center is at position xf, where xf>xi
Explanation / Answer
W.D= Fs
part a
W.D= F1 (Xf-Xi) N-m
part B
W.D= F1 (Xi-Xf) N-m
part C
Net W.D= (F1-F2)*(Xf-Xi) N-m
Part D
when Both force r equal then
Net W.D. =Zero
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