-Do 1-7 -Show work and do not miss answer on purpose if not points will be award

Question

-Do 1-7

-Show work and do not miss answer on purpose if not points will be awarded randomly

This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page - find all choices before answering. We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 5-6 g. Find the number of atoms in a nickel coin. Each mole (6-2 Times 1 23 atoms) has a mass of about 58.1 g. Answer in units of atoms Find the number of electrons in the coin. Each nickel atom has 28 electrons/atom. Answer in units of electrons Find the magnitude of the charge of all these electrons. Answer in units of C A strong lightning bolt transfers an electric charge of about 1 C to Earth (or vice versa). How many electrons are transferred? Avo-gadros number is 6.22 Times 1 23 /mol, and the elemental charge is 1.62 Times 1 9 C. If each water molecule donate one electron, how much water is ionized in the lightning? One mole of water has a mass of 17.9 g/mol. Answer in units of g A strong lightning bolt transfers about 23 C to Earth. How many electrons are transferred? The elementary charge is 1.6218 Times 1-19 C. You have .4 kg of water. One mole of water has a mass of 18 g/mole and each molecule of water contains 1 electrons since water is H2O. What is the total electron charge contained in this volume of water? The elementary charge is 1.6 Times 1-19C. Answer in units of C If an object contains more electrons than protons, it is said to be energized. positively charged. negatively charged. neutral. Two charged particles of equal magnitude (+ Q and -Q) are fixed at opposite corners of a square that lies in a plane (see figure below). A test charge -q is placed at a third corner. What is the direction of the force on the test charge due to the two other charges?

Explanation / Answer

001 - Mass of nickel coin = 5.6 g

Mass of each mole = 58.1 g

So no of moles in coin = 5.6/58.1 = 0.096

No of atoms = 0.096*6.02*10^23 = 5.8*10^22

002 Each atom has 28 electrons

No of electrons in coin = 5.8*10^22*28 = 1.62*10^24

003 Charge on each electron = 1.6*10^-19 C

Total charge on coin = 2.6*10^5 C

004 Charge on each electron = 1.6*10^-19 C

Charge transfered = 10C

So no of electrons tranfered = 6.25*10^19

005 No of water molecules ionized = 6.25*10^19

Moles of water ionized = 1.04*10^-4

Mass = 1.86*10^-3 g

006 Elementary charge = 1.60218*10^-19

Charge transferred = 10 C

Electrons transferred = 6.24*10^19

007 Mass of water = 400 g

Moles of water = 400/18 = 22.22

Molecules of water = 1.34*10^25

No of electrons = 1.34*10^26

So charge = 8.375*10^6 C

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