Problem A solid substance that has a latent heat of fusion L f melts at a temper
ID: 3892346 • Letter: P
Question
Solution Making use of Equation 18.10 and that the latent heat of fusion Q = mLf, (Eq. 17.5), we find the following. Note that we are able to remove Tm from the integral because the process is isothermal.
Explanation / Answer
melting is a phase change process so temperature of ice will not change,
change in entropy = change in Q/T
now Q = m*L L = latent heat of fusion of water = 334 KJ/kg
= 1.6*334000
= 534400 J
change in entropy = 534400/273
= 1957.51 J/K
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