LAB: C++/C common string functions part 2: reverse, reverse new strchr strrchr,
ID: 3885355 • Letter: L
Question
LAB: C++/C common string functions part 2: reverse, reverse new strchr strrchr, strncat strstrreplace, replace str Code and Algorithm Design This lab, based on K and R (aka: THE C PROGRAMMING LANGUAGE by Kemighan and Ritchie). is designed to give more practice in working with common C library functions used in C++C (please refer to Chapter 5.5 when needed, or related sections (marked in the text). char reverse (char* q): char reverse_new (const char q) / make a new string that is reversed char strchr_(chars, char c): char strrchr (char s, char c): /I reverse a string in place / find the first occurrence of c find the last occurrence of c .II concatenate up to n characters from t onto the end ofs char strncat (char* s. const char* t. size t n): char replace (char s. char c, char d); I replace all occurrences of c with d char replace str_(char s. char t.char u): .1 replace alt occurrences of substring t with new substring u All of these functions should be imalemented with pointers. Students will also show each of the algorithms using spreadsheets (as in the previous lab). Don't forget to check: when needed. ncludeExplanation / Answer
here you have the first four methods declared in the question you have provided.
char* reverse_(char *q) {
char tmp;
int i, l = strlen(q);
for (i = 0; i < l/2; i++) {
tmp = q[i];
q[i] = q[l - 1 - i];
q[l - 1 - i] = tmp;
}
return q;
}
char* reverse_new_(const char *q) {
char* newString;
int i, l = strlen(q);
newString = char[strlen(q) + 1];
for (i = 0; i < l; i++) {
newString[i] = q[l - 1- 1];
}
newString[l] = q[l] ;
return newString;
}
char* strchr_ (char* s, char c) {
int i, l = strlen(q);
for (i = 0; i < l; i++) {
if (s[i] == c)
return s + i;
return NULL;
}
char* strrchr_ (char* s, char c) {
int i, l = strlen(q), index = -1;
for (i = 0; i < l; i++) {
if (s[i] == c)
index = i;
if (index >= 0)
return s + index;
return NULL;
}
due to chegg protocol, we can answer 4 questions at a time only, so remauining four goes unanswered. please co-operate
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