Write a C program that will calculate the voltage across the capacitor in the fo

Question

Write a C program that will calculate the voltage across the capacitor in the following circuit as time increases from 0 to 1 second in increments of 1/15 second, assuming that the switch is closed at time 0.

The voltage across the capacitor at time t is given by the following equation:

Constants: In this circuit, V = 10 volts, R = 3,000 ohms, and C = 50 x 10-6 farads. The circuit has a

time constant , which depends on the resistance, R, and the capacitance, C, as = R x C = 0.15 second.

1) Name your program voltage.c

2) Use a for loop.

3) Use the math library function exp(x) to compute ex. You will need to include the system header file math.h.

4) On Unix you will need –lm in your command line to tell the Linker to search the math library.

5) Use macro definition for all the constants.

6) Format the output so the output looks like the following. The time and voltage should display two digits after the decimal point.

Explanation / Answer

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#define V 10
#define R 3000;
#define C 50*10^-6

int main()
{ int i;
float t[16]= {0.00,0.07,0.13,0.20,0.27,0.33,0.40,0.47,0.53,0.60,0.67,0.73,0.80,0.87,0.93,1.00};
float v[16];
float T= 0.15; //T = R*C

for(i=0;i<16;i++)
{
v[i] = V * (1 - exp(-t[i]/T)); //v(t)= V * (1 - e^(-t/T))

}
printf(" time(sec) voltage "); // to display the output
for(i=0;i<16;i++)
printf(" %.2f %.2f ",t[i],v[i]);
}

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