Write a menu driven shell linux script program on the system to do the following
ID: 3882473 • Letter: W
Question
Write a menu driven shell linux script program on the system to do the following tasks:
Please use the needed grep and cut commands to get the specific names please.
1. Display the IP address and the name of the machine only
2. Display all users currently on the system (id and full name only)
3. Display the server IP address, the netmask, and the broadcast addresses only
4. Enter user’s login id and display all processes belong to the entered id
5. Count how many login IDs on the server
6. Exit Program
Enter selection: _
Note: Your program should run forever until the user chooses to quit - (option 6).
Explanation / Answer
show menu(){
echo "menu"
echo "enter 1 ip address name"
echo "enter 2 users"
echo " enter 3 netmask broadcast"
echo "enter 4 login id process"
echo "enter 5 login id"
echo "enter 6 exit"
read -p "please select a number in menu" i
return $i
}
while [["$i"!="6"]]
do if[["$i"=="1"]];then
echo $USER
ip addr show |grep -w inet|grep -v 127.0.0.1|awk '{print $2}'|cut -d "/" -f1
elif [["$i"=="2"]];then
who
elif [["$i"=="3"]];then
echo "mask ip"
ip addr show|grep -w inet|grep -v 127.0.0.1|awk '{print $2}'|cut -d "/" -f2
echo "broadcast ip"
ip addr show|grep -w inet|grep -v 127.0.0.1|awk '{print $4}'
elif [["i"=="4"]];then
echo "user id"
echo $uid
echo "process"
ps -el|grep -i $uid
elif [["i"=="5"]];then
log= who| wc -l
echo "$log"
fi
show menu
done
i=$?
exit;;
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