[C++JTask Create a program that calculate the IC in the tube. Each commands li:

Question

[C++JTask Create a program that calculate the IC in the tube. Each commands li: input IC in the left side of tube ri : input IC in the right side of tube Ir : Move IC from left side to right side rr Move IC from right side to left side Input First line : Integer M (1SMS 1,000) for how much of the commands. Next line : In each line must begin with "li" or "ri" or "Ir" or "rr". If begin with li or ri must follow by the number of IC. Example Input 8 ri 1 ri 2 ri 3 li 20 ri 100 Ir ri 1000 Output 1000 123 100 20

Explanation / Answer

#include<iostream>
#include<list>
#include<iterator>
#include<cstring>
#include<cstdlib>
using namespace std;
int main()
{
   int cmdCount, tempVar;
   list <int> mylist;
   char *cmdstring;
   string cmd;
   cout<<"Enter how many commands:";
   cin>>cmdCount;
   cin>>ws; /*Clearing the input buffer */
   while(cmdCount--)
   {
       getline(cin, cmd); /* Get string input along with line */
       cmdstring = (char*)cmd.c_str();
       if(0 == strncmp("li", cmdstring, 2))
       {
           tempVar = atoi(&cmdstring[3]); /*Convert input to integer and add to front(left of the list) */
           mylist.push_front(tempVar);
       }  
       else if(0 == strncmp("ri", cmdstring, 2))
       {
           tempVar = atoi(&cmdstring[3]); /*Convert input to integer and add to front(right of the list) */
           mylist.push_back(tempVar);
       }
       else if(0 == strncmp("lr", cmdstring, 2))
       {
           if(mylist.empty() == false) /* If list is not empty, get element from front(left) and delete it from front. Then add it in the back(right) */
           {
               tempVar = mylist.front();
               mylist.pop_front();
               mylist.push_back(tempVar);
           }
       }
       else if(0 == strncmp("rr", cmdstring, 2))
       {
           if(mylist.empty() == false) /* If list is not empty, get element from back(right) and delete it from back. Then add it in the front(left) */
           {
               tempVar = mylist.back();
               mylist.pop_back();
               mylist.push_front(tempVar);
           }
       }

   }
   cout<<endl;
   for(list <int> :: iterator it = mylist.begin(); it != mylist.end(); ++it)
       cout<< *it <<endl;
   return 0;
}

/* Note :- If the ouput is not your desired output, then you can explain the output once. I have done the program as your requirement stated. Thanks. */

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