#3 Ouestion 1 The object of first normal form in the normalization process is to
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Question
#3
Ouestion 1
The object of first normal form in the normalization process is to:
Question 2
If a table has a single column primary key and its already in first normal form, what can we say about that table?
Question 3
1 out of 1 points
When defining functional dependence from column A to column B, so that A ? B, this means that
Question 4
For a table to be in third normal form (3NG) it must be in second normal form and _____.
Question 5
When starting the information level design for a database, we must represent each ____ as a collection of tables.
Question 6
When working with an entity (table), we can create a(n) _____ to be that entity's primary key and also make it visible to the users so that they can identity each unique record.
Question 7
Which of these is NOT one of the steps when building a User View?
Question 8
If col1 is the PK of Table1 and col5 is the PK of Table2, the following alternative table structures is an example of a _____ relationship.
Table1(col1, col2, col3) Table1(col1, col2, col3, col5)
Table2(col5, col6, col1) OR Table2(col5, col6)
Question 9
If a given table structure has too many null values, we can ____
Question 10
In the Entity Relationship Model, an entity with a minimum cardinality of zero represents a ________
Explanation / Answer
If you post more than 1 question, as per chegg guidelines I have to solve only 1 question.
Ques 1.
The objective of first normal form is to make sure that each attribute contains only atomic values or contains only one value only.
Ques 2.
We can say that the table is also in 2nd Normal Form as there is no functional dependency.
Here, the candidate key contains only 1 element which is the primary key attribute. As the candidate key contains only 1 attribute and so no non-prime attribute is dependent on any proper subset of any candidate key of the relation. Hence, the table is in 2nd Normal Form.
Ques 3.
It means that we can uniquely find each value of column B from the corresponding value of column A. It means that for each unique value of A, there is a unique value in B. Hence, if we know A, we can find each element of B.
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