write a function that returns the first node of a linked list, Your function\'s

ID: 3875949 • Letter: W

Question

write a function that returns the first node
of a linked list,

Your function's prototype is as follows:

int abc(struct node *head, int *x)

and operates as follows:

abc is an array of struct nodes *containing a linked list*
abc[0] is assumed to be a sentinal node, and is always present
abc[0].next is the index of the first data node
If there is a first data node, your function should return that value as the function value, and should set *x to 0
If however the list is empty (no first data node exists), the function should return 0, and should set *x to 1

Explanation / Answer

Here is code for the function, I also written the stucture of link list and relevant data in main should be written by user according to need.

Comments are also provided to clear it.

#include <stdio.h>
struct node {
    int data;
    struct node* next;
};

int abc (struct node* head, int* x)
{
    if(head-> data == 0) //check if yhe list is empty
        //sential node will have value
    {
        *x = 1;
        return 0;
    }

    else {
        *x = 0;
        return head-> next-> data;
        //data of first node;
    }

}
int main(int argc, char const *argv[])
{

    return 0;
}

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write a function that returns the first node of a linked list, Your function\'s

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