C++: So, the code here is working but, i would like to add in a yes and no input

Question

C++:

So, the code here is working but, i would like to add in a yes and no input string or loop. Open to any suggestions. Thanks for reading! *NOTE: the yes and no command begins at line 66.*

#include <iostream>

using namespace std;

int main()

{

// Constants

const int QUARTERS = 25; // Quarter value

const int DIMES = 10; // Dime value

const int NICKELS = 5; // Nickle value

const int PENNIES = 1; // Penny value

// Variables

int change; // To hold value of change

int numQuarters; // To hold value of quarter

int numDimes; // To hold value of dime

int numNickels; // To hold value of nickel

int numPennies; // To hold value of penny

cout << "Enter a positive number of coins, >= 0 ";

cin >> change;

if (change > 0)

{

cout << "The following is a breakdown of the least possible number of coins" << endl;

// Calculate least possible number of coins

numQuarters = change / QUARTERS;

change -= numQuarters * QUARTERS;

numDimes = change / DIMES;

change -= numDimes * DIMES;

numNickels = change / NICKELS;

change -= numNickels * NICKELS;

numPennies = change / PENNIES;

change -= numPennies * PENNIES;

// Display breakdown of least possible number of coins

if (numQuarters != 0 && numQuarters == 1)

cout << "There is " << numQuarters << " Quarter ";

if (numQuarters != 0 && numQuarters > 1)

cout << "There are " << numQuarters << " Quarters ";

if (numDimes != 0 && numDimes == 1)

cout << "There is " << numDimes << " Dime ";

if (numDimes != 0 && numDimes > 1)

cout << "There are " << numDimes << " Dimes ";

if (numNickels != 0 && numNickels == 1)

cout << "There is " << numNickels << " Nickel ";

if (numNickels != 0 && numNickels > 1)

cout << "There are " << numNickels << " Nickels ";

if (numPennies != 0 && numPennies == 1)

cout << "There is " << numPennies << " Penny ";

if (numPennies != 0 && numPennies > 1)

cout << "There are " << numPennies << " Pennies ";

cout << "Would you like to try another number? (y/Y). Anything else will quit " << endl;

}

else

{

cout << "You entered zero, there are no coins for zero!" << endl;

}

system("pause");

return 0;

}

Explanation / Answer

You can get a character variable having y or n depending on your choice and use a while loop till the variable has n assigned to it. Try it and comment if you still have problem. Happy learning :)

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