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is summer I had some work done on my house. I had my 1-foundation fixed 2- porch

ID: 387416 • Letter: I

Question

is summer I had some work done on my house. I had my 1-foundation fixed 2- porch resealed roof repaired and 4- house power washed.I looked online and was surprised that many companies do all of these of these things. That being said, I was shocked when each of four companies Ifound said they were so busy up they could only schedule one of the four things I needed done within a month Thus, I was forced to contract each of these four repairs to only one company. Below are the bids that each company gave me for the things I needed completed Bids by Company Component Foundation Fixed Porch Resealed Roof Repaired House Power washed $10,000 $11,250 $9,650 $10,350 $400 $2,310 $500 $500 $380 $2,240 $2,205 $2,500 $502 $450 $425 $445 Assuming all the companies can perform each task equally as well, to which company should I hire to each task, so I can minimize my total cost? a. Formulate this problem in Solver and solve it, what is the optimal answer?

Explanation / Answer

First let us put up the companies as ranking in terms of lowest bidders like

L1 – lowest bid ;

L2 – 2nd lowest bid

L3 – 3rd lowest bid

L4 – highest bid

We will see following

Minimum Bid $

Component

(L1)

Company

(L2) bid $

Company

(L3) Bid $

Company

(L4) bid $

Company

Foundation Fixed

9650

C

10000

A

10350

D

11250

B

Porch Resealed

380

B

400

A

450

D

500

C

Roof Repaired

2205

C

2240

B

2310

A

2500

D

House Power Washed

425

C

445

D

500

A

502

B

As we have restriction that one company do only job therefore first we have to see first that where is the maximum difference between L1 and L2

Component

difference in L1 and L2

in $

Foundation Fixed

350

Porch Resealed

20

Roof Repaired

35

House Power Washed

20

Therefore we can see that in Foundation Fixed difference between L1 and L2 bid is maximum as $350.

So for Foundation Fixed we will have to select Company “C with bid as $ 9650 as the company to become optimum

Now Company “C” is selected , we cannot select Company “C” for second time.

Therefore if now difference between L1 and L2 bid in remaining 3 jobs , Porch Resealed is having maximum difference of $35 between L1 and L2 bids, But since we have already select Company “C” earlier therefore we will select L2 bid $2240 by company “B” for Roof Repaired job.

Now 2 jobs are fixed and remaining jobs are Porch Resealed and House Power Washed.

Now we will to difference between L2 and L3 bids for Porch Resealed and House Power Washed jobs

difference in L2 and L3 bids in $

Porch Resealed

50

House Power Washed

55

So we will select L3 bid for House Power Washed first

best bid for House Power Washed is by Company “C but Company “C” is selected , we cannot select Company “C” for second time. So we will choose Company D or House Power Washed here with $ 445 bid

Remaining job is Porch Resealed and only option left is company A for Porch Resealed job with bid of $400.

So our optimum selection of companies for minimizing the cost will be as below:

Job

Bid

Company

Foundation Fixed

$9650

C

Porch Resealed

$400

A

Roof Repaired

$2240

B

House Power Washed

$445

D

Total

$12735

                   

Minimum Bid $

Component

(L1)

Company

(L2) bid $

Company

(L3) Bid $

Company

(L4) bid $

Company

Foundation Fixed

9650

C

10000

A

10350

D

11250

B

Porch Resealed

380

B

400

A

450

D

500

C

Roof Repaired

2205

C

2240

B

2310

A

2500

D

House Power Washed

425

C

445

D

500

A

502

B