# File: mlIfElse.asm # Author: Landon Stobart # Date: 09/13/2017 # Purpose: Prac
ID: 3872107 • Letter: #
Question
# File: mlIfElse.asm
# Author: Landon Stobart
# Date: 09/13/2017
# Purpose: Practice if-else logic
#----------------------------------------------
# WRITE MIPS CODE FOR THE FOLLOWING C++ CODE:
#include
#include
#using namespace std;
#void main()
#{
# //declare variables
# string result;
# int x;
# //prompt for, read in a value for x
# cout << "Please enter a value for x (integer): ";
# cin >> x;
#
# ==========================================================
# //PROBLEM1 - if x has a value of 3 or 4, print "ddd", else print "eee"
# result = "";
# if(x==3 || x==4) result = result + "ddd";
# else result = result + "eee";
# cout << "1. " << result << endl;
#
# =============================================================
# //PROBLEM2 - if x is less than 5 and greater than 2,
# // then check to see if it is even. If it is even,
# // print "ddd". If its not even, the original "ccc" is printed.
# // But if x was not less than 5 and greater than 2,
# // print "eee".
# result = "ccc";
# if (x < 5 && x > 2)
# {
# if (x%2 == 0) result = "ddd";
# }
# else result = "eee";
# cout << "2. " << result << endl;
#
# ==========================================================
# //PROBLEM3 - if x has a value if 2, print "bbb"
# // if x has a value of 3, print "ccc"
# // if x has a value of 4, print "ddd"
# // if x has a value other than 2, 3, or 4 print "eee"
# result = "";
# switch (x)
# {
# case 2: result = result + "bbb"; break;
# case 3: result = result + "ccc"; break;
# case 4: result = result + "ddd"; break;
# default: result = result + "eee";
# }
# cout << "3. " << result << endl;
#
# =========================================================
# //PROBLEM4 - if x has a value of 4, print "ddd"
# // if x has a value of 3, print "ccc"
# // any other value (not 3 or 4), print "eee"
# result = "";
# if (x==4) result = result + "ddd";
# else if (x==3) result = result + "ccc";
# else result = result + "eee";
# cout << "4. " << result << endl;
#
# }//end main()
.data
.eqv SYS_PRINT_WORD 1 #word, byte, character
.eqv SYS_PRINT_FLOAT 2 #float
.eqv SYS_PRINT_DOUBLE 3 #double
.eqv SYS_PRINT_TEXT 4 #text (zero terminated)
.eqv SYS_INPUT_WORD 5 #input word
.eqv SYS_EXIT 10 #terminate
# //declare variables
# string result;
# int x;
result: .asciiz "0123456789012345" #max of 16 chars
x: .word 0 # copy of $s5
endl: .asciiz " "
tx_prompt: .asciiz "Please enter a value for x (integer): "
tx_bbb: .asciiz "bbb"
tx_ccc: .asciiz "ccc"
tx_ddd: .asciiz "ddd"
tx_eee: .asciiz "eee"
prob1_label: .asciiz "1. "
prob2_label: .asciiz "2. "
prob3_label: .asciiz "3. "
prob4_label: .asciiz "4. "
.text
.globl main
main:
# //prompt for, read in a value for x
# cout << "Please enter a value for x (integer): ";
# cin >> x;
la $a0, tx_prompt # load address of prompt for syscall
li $v0, SYS_PRINT_TEXT # specify Print String service
syscall # print the prompt string
li $v0, SYS_INPUT_WORD # specify Read Integer service
syscall # Read the number. After this instruction, the number read is in $v0.
add $s5, $v0, $zero # transfer the number to s5
la $t0, x
sw $s5, 0($t0) # s5 = x = input word number
la $s4, result # s4 = address of result string
# //PROBLEM1 - if x has a value of 3 or 4, print "ddd", else print "eee"
# result = "";
# if(x==3 || x==4) result = result + "ddd";
# else result = result + "eee";
# cout << "1. " << result << endl;
sb $zero, 0($s4)
li $t1, 3 # x==3?
beq $s5, $t1, ddd1 # if yes then branch
li $t1, 4 # x==4?
beq $s5, $t1, ddd1 # if yes then branch
#else
move $a0, $s4 # x not 3 and x not 4
la $a1, tx_eee
jal concatstr #result = result plus "eee"
j prt1
#if is true
ddd1:
move $a0, $s4 #x =3 or x=4
la $a1, tx_ddd
jal concatstr
prt1:
la $a0, prob1_label
li $v0, 4
syscall
move $a0, $s4 #print result
li $v0, 4
syscall
la $a0, endl
li $v0, 4
syscall
# //PROBLEM2 - if x is less than 5 and greater than 2,
# // then check to see if it is even. If it is even,
# // print "ddd". If its not even, the original "ccc" is printed.
# // But if x was not less than 5 and greater than 2,
# // print "eee".
# result = "ccc";
# if (x < 5 && x > 2)
# {
# if (x%2 == 0) result = "ddd";
# }
# else result = "eee";
# cout << "2. " << result << endl;
addi $t0, $zero, 5
addi $t1, $zero, 2
slt $t2, $s5, $t0
beq $t2, $zero, eee2
slt $t3, $s5, $t1
bne $t3, $zero, eee2
---------------------------------------------This is as far as a I am, problem 1 is done, i need 2,3 and 4
Explanation / Answer
// Problem-2
#include <iostream>
using namespace std;
int main()
{
string result="";
int x;
cout << "Enter an integer: ";
cin >> x;
// Check if x is between 5 and 2
if ( x <5 && x>2)
{
//check if provided number is even
if(x%2==0){
result=result+"ddd";
cout << result << endl;
}
//if x lies between 2 and 5 and not an even number then execute below loop
else{
result=result+"ccc";
cout << result << endl;
}
}
// if x is not lessthan 5 and greater than 2 then below loop will be executed
else
{
result=result+"eee";
cout << result << endl;
}
return 0;
}
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