Need help figuring out why my code doesn\'t work. I have: void lowerNoPunctuatio

Question

Need help figuring out why my code doesn't work. I have:

void lowerNoPunctuation(string str, string p){

int i,j;

for(i=0;i<p.length();i++){

int b = str.length();

for(j=0;j<b;j++){

if(str[j] == p[i]) str.erase(j,1);

b = str.length()

}

}

for(i=0;i<str.length();i++) if(isupper(str[i])) str[i] = (char)((int)str[i]+32);

}

I keep getting:

When comparing sentences we are often not interested in differences in case (UPPERCASE vs lowercase) or punctuation. For this problem, you will be writing a function that takes two string parameters- sentence and punctuation and returns the same string in lowercase (remember the built-in tolower function) and with givern punctuation removed. You must use nested loops. The built lowerNoPunctuation returns a string and takes a two strings as parameters string lowerNoPunctuation(string str, string punch) //Your code here Example Output: string str-"Hello, my name is Inigo Montoya. You killed my father. Prepare to die!" string punct - ".,!? string newStr = lowerN°Punctuation(str, punct) cout

Explanation / Answer

//use the below program to convert all to lowercase and remove the punctuations.

//your above error is related to the headers.

#include <string>
#include <iostream>
#include <cctype>

int main() {

    std::string str = "this. is my string. it's here.";

    for (int i = 0, len = str.size(); i < len; i++)
    {
        if (ispunct(str[i]))
        {
            str.erase(i--, 1);
            len = str.size();
        }
    }
   for(i=0;i<=strlen(str);i++)
   {
        if(str[i]>=65 && str[i]<=92)
        {
       str[i]=str[i]+32;
        }
}
    std::cout << str;
    return 0;
}

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